Question

Answer 1

a: \(\left(2x-5\right)^2-4x\left(x-3\right)=0\)

=>\(4x^2-20x+25-4x^2+12x=0\)

=>-8x+25=0

=>-8x=-25

=>\(x=\frac{25}{8}\)

b: \(2\left(x+5\right)-x^2-5x=0\)

=>2(x+5)-x(x+5)=0

=>(x+5)(2-x)=0

=>\(\left[\begin{array}{l}x+5=0\\ 2-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=-5\\ x=2\end{array}\right.\)

c: \(6x^2-7x+2=0\)

=>\(6x^2-4x-3x+2=0\)

=>2x(3x-2)-(3x-2)=0

=>(3x-2)(2x-1)=0

=>\(\left[\begin{array}{l}3x-2=0\\ 2x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac23\\ x=\frac12\end{array}\right.\)