Đặt \(\frac{a}{2022}=\frac{b}{2021}=\frac{c}{2020}=k\)
=>a=2022k; b=2021k; c=2020k
\(4\left(a-b\right)\left(b-c\right)\)
=4(2022k-2021k)(2021k-2020k)
\(=4\cdot k\cdot k=4k^2\)
\(\left(a-c\right)^2=\left(2022k-2020k\right)^2=\left(2k\right)^2=4k^2\)
Do đó: \(4\left(a-b\right)\left(b-c\right)=\left(a-c\right)^2\)
