Question

Answer 1

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Answer 2

\(x^2-x=0\\ \Leftrightarrow x\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

15,\(x^2-5x+6=x^2-2x-3x+6=\left(x^2-2x\right)-\left(3x-6\right)=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)

Answer 3

x²-x=0

-2x²=0

=>-2x²=0 nếu x=0

Vậy x=0

Câu 15: x²-5x+6=x²-3x-2x+6=(x²-3x)-(2x-6)=x(x-3)-2(x-3)

=(x-2)(x-3)