Question

Answer 1

\(\dfrac{x^2-2x}{x^2-4}=\dfrac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{x}{x+2}\)

Answer 2

\(\dfrac{x}{x+2}\)

Answer 3

\(\dfrac{x^2-2x}{x^2-4}=\dfrac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{x}{x+2}\)

Answer 4

= \(\dfrac{X\left(X-2\right)}{\left(X-2\right)\left(X+2\right)}\)

= \(\dfrac{X}{X+2}\)

Answer 5

Giải: 

\(\dfrac{x^2-2x}{x^2-4}\) = \(\dfrac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}\)= \(\dfrac{x}{\left(x+2\right)}\)

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