5,\(x:y:z=4:2:7\Rightarrow\dfrac{x}{4}=\dfrac{y}{2}=\dfrac{z}{7}\)
Đặt \(\dfrac{x}{4}=\dfrac{y}{2}=\dfrac{z}{7}=k\Rightarrow x=4k;y=2k;z=7k\)
\(M=\dfrac{2x+3y-z}{4x+5y+z}=\dfrac{2.4k+3.2k-7k}{4.4k+5.2k+7k}=\dfrac{8k+6k-7k}{16k+10k+7k}=\dfrac{7k}{33k}=\dfrac{7}{33}\)
