Question

Answer 1

\(a,=\sqrt{36}-\sqrt{16}=6-4=2\\ b,=\left|\sqrt{11}-3\right|=\sqrt{11}-3\\ c,=10\sqrt{3}+3\sqrt{3}-6\sqrt{3}=7\sqrt{3}\\ d,=\dfrac{\sqrt{\left(\sqrt{3}-1\right)^2}}{\sqrt{2}\left(\sqrt{3}-1\right)}=\dfrac{\sqrt{3}-1}{\sqrt{2}\left(\sqrt{3}-1\right)}=\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2}\)