Câu 9:
\(a,P=\dfrac{\sqrt{a}-1}{\sqrt{a}\left(\sqrt{a}+1\right)}\cdot\dfrac{\left(\sqrt{a}+1\right)^2}{\sqrt{a}-1}=\dfrac{\sqrt{a}+1}{\sqrt{a}}\\ b,P>2\Leftrightarrow\dfrac{\sqrt{a}+1}{\sqrt{a}}-2>0\Leftrightarrow\dfrac{1-\sqrt{a}}{\sqrt{a}}>0\\ \Leftrightarrow1-\sqrt{a}>0\left(\sqrt{a}>0\right)\\ \Leftrightarrow0< a< 1\)