Bài 10:
\(N=\frac{3^{14}\cdot15+3^{19}:3^5\cdot279}{9^7\cdot63}\)
\(=\frac{3^{14}\cdot3\cdot5+3^{14}\cdot3^2\cdot31}{3^{14}\cdot3^2\cdot7}=\frac{3^{15}\cdot5+3^{16}\cdot31}{3^{16}\cdot7}\)
\(=\frac{3^{15}\left(5+3\cdot31\right)}{3^{16}\cdot7}=\frac13\cdot\frac{5+93}{7}=\frac13\cdot\frac{98}{7}=\frac{14}{3}\)
