Question

Answer 1

Áp dụng t/c dtsbn ta có:

\(\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{z}{6}=\dfrac{x-y}{5-3}=\dfrac{4}{2}=2\)

\(\dfrac{x}{5}=2\Rightarrow x=10\\ \dfrac{y}{3}=2\Rightarrow y=6\\ \dfrac{z}{6}=2\Rightarrow z=12\)

Answer 2

áp dụng t/c dtsbn:

\(\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{z}{6}=\dfrac{x-y}{5-3}=2\)

\(\Rightarrow\left\{{}\begin{matrix}x=10\\y=6\\z=12\end{matrix}\right.\)

Answer 3

Áp dung tcdtsbn , ta có:

\(\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{z}{6}=\dfrac{x}{5}-\dfrac{y}{3}=\dfrac{4}{2}=2\)

\(\Rightarrow\left\{{}\begin{matrix}x=10\\y=6\\z=12\end{matrix}\right.\)