Question

Answer 1

x=4

Answer 2

\(\Leftrightarrow\left\{{}\begin{matrix}x-3\ge0\\2x-7=\left(x-3\right)^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge3\\2x-7=x^2-6x+9\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x\ge3\\x^2-8x+16=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge3\\x=4\left(tm\right)\end{matrix}\right.\Leftrightarrow x=4\)