a) m⊥a,n⊥a⇒m//n
b) \(\widehat{B_1}=\widehat{D_1}=70^o\left(2.góc.so.le.trong\right)\)
\(\widehat{D_1}=\widehat{D_2}=70^o\left(2.góc.đôi.đỉnh\right)\)
c) Ta có: \(\widehat{B_1}+\widehat{D_1}=70^o+110^o=180^o\)
mà 2 góc này slt\(\Rightarrow\)m//p mà m⊥a⇒p⊥a
