\(a,A=\dfrac{\sqrt{x}-1}{\sqrt{x}\left(\sqrt{x}+2\right)}\cdot\dfrac{\left(\sqrt{x}+2\right)^2}{1-\sqrt{x}}=\dfrac{-\left(\sqrt{x}+2\right)}{\sqrt{x}}\\ b,A=\dfrac{5}{3}\Leftrightarrow-3\left(\sqrt{x}+2\right)=5\sqrt{x}\)
Vì \(5\sqrt{x}\ge0>-3\left(\sqrt{x}+2\right)\) nên PT vô nghiệm

