\(PT\Leftrightarrow\sqrt{3x+1}=4x+1\\ \Leftrightarrow3x+1=16x^2+8x+1\\ \Leftrightarrow16x^2+5x=0\\ \Leftrightarrow x\left(16x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\x=-\dfrac{5}{16}\left(ktm\right)\end{matrix}\right.\Leftrightarrow x=0\)

