Question

Answer 1

\(a,A=\dfrac{x-5\sqrt{x}+4}{\sqrt{x}\left(\sqrt{x}-2\right)}:\dfrac{x-4-x}{\sqrt{x}\left(\sqrt{x}-2\right)}\\ A=\dfrac{-x+5\sqrt{x}-4}{4}\\ b,A=\dfrac{-\dfrac{4}{25}+5\cdot\dfrac{2}{5}-4}{4}=-\dfrac{54}{25}\cdot\dfrac{1}{4}=-\dfrac{27}{50}\\ c,x-3A=1\\ \Leftrightarrow x+\dfrac{3\left(x-5\sqrt{x}+4\right)}{4}=1\\ \Leftrightarrow\dfrac{4x+3x-15\sqrt{x}+12}{4}=1\\ \Leftrightarrow7x-15\sqrt{x}+8=0\\ \Leftrightarrow\left[{}\begin{matrix}\sqrt{x}=\dfrac{8}{7}\\\sqrt{x}=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{64}{49}\\x=1\end{matrix}\right.\)