Bài 9:
Để \(\left(d_1\right)//\left(d_2\right)\Leftrightarrow\left\{{}\begin{matrix}2m^2-m=1\\m^2+m\ne2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2m^2-m-1=0\\\left(m+2\right)\left(m-1\right)\ne0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}m=1\\m=-\dfrac{1}{2}\end{matrix}\right.\\\left\{{}\begin{matrix}m\ne1\\m\ne-2\end{matrix}\right.\end{matrix}\right.\Leftrightarrow m=-\dfrac{1}{2}\)
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