\(1,=\sqrt{5}+1+\sqrt{5}-1=2\sqrt{5}\\ 2,=\sqrt{\left(2+\sqrt{3}\right)^2}-\sqrt{\left(\sqrt{3}-\sqrt{2}\right)^2}=2+\sqrt{3}-\sqrt{3}+\sqrt{2}=2+\sqrt{2}\\ 3,=\sqrt{\left(\sqrt{3}+1\right)^2}+\sqrt{\left(\sqrt{2}-1\right)^2}=\sqrt{3}+\sqrt{2}\\ 4,=\sqrt{\left(\sqrt{2}+1\right)^2}-\sqrt{\left(2-\sqrt{2}\right)^2}=\sqrt{2}+1-2+\sqrt{2}=2\sqrt{2}-1\\ 5,=\dfrac{\sqrt{5}+7}{-44}+\dfrac{1+\sqrt{7}}{-3}=\dfrac{-3\sqrt{5}-21-44-44\sqrt{7}}{132}=\dfrac{-3\sqrt{5}-44\sqrt{7}-65}{132}\\ 6,=\dfrac{3\left(\sqrt{7}+2\right)}{3}+\dfrac{2\left(3-\sqrt{7}\right)}{2}=\sqrt{7}+2+3-\sqrt{7}=5\\ 7,=\dfrac{\sqrt{3}+2}{-1}+\dfrac{\sqrt{3}\left(\sqrt{3}+2\right)}{\sqrt{3}+2}=-\sqrt{3}-2+\sqrt{3}=-2\\ 8,=\dfrac{\sqrt{3}\left(\sqrt{5}+1\right)}{\sqrt{5}+1}-\dfrac{2\left(\sqrt{3}+1\right)}{2}\\ =\sqrt{3}-\sqrt{3}-1=-1\)
