Ta có: f(x)=\(x^{23}-x^9+x^6-x^2+1\)
\(=\left(x^{23}+x^6\right)-\left(x^9+x^2\right)+1\)
\(=x^6\left(x^{17}+1\right)-x^2\left(x^7+1\right)+1\)
\(=x^6\left(x+1\right)\left(x^{16}-x^{15}+x^{14}-x^{13}+\cdots+1\right)-x^2\left(x+1\right)\left(x^6-x^5+x^4-\cdots+x^2-x+1\right)+1\)
=(x+1)\(\left\lbrack x^6\left(x^{16}-x^{15}+x^{14}-x^{13}+\cdots+1\right)-x^2\left(x^6-x^5+x^4-x^3+\cdots+x^2-x+1\right)\right\rbrack\) +1
=>f(x) chia x+1 dư 1
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