Question

Answer 1

\(\Leftrightarrow\left(4x^3+8x^2+3x^2+6x-x-2+7\right)⋮\left(x+2\right)\\ \Leftrightarrow\left[\left(x+2\right)\left(4x^2+3x-1\right)+7\right]⋮\left(x+2\right)\\ \Leftrightarrow x+2\inƯ\left(7\right)=\left\{-7;-1;1;7\right\}\\ \Leftrightarrow x\in\left\{-9;-3;-1;5\right\}\)

Answer 2

\(\Leftrightarrow4x^3+8x^2+3x^2+6x-x-2+7⋮x+2\)

\(\Leftrightarrow x+2\in\left\{1;-1;7;-7\right\}\)

hay \(x\in\left\{-1;-3;5;-9\right\}\)