Question

Answer 1

\(\dfrac{x}{7}=\dfrac{y}{3}=\dfrac{x-y}{7-3}=\dfrac{16}{4}=4\)

⇒ \(\dfrac{x}{7}=4\Leftrightarrow x=4.7=28\)

⇒ \(\dfrac{y}{3}=4\Leftrightarrow y=4.3=12\)

Answer 2

Áp dụng tcdtsbn , ta có:

\(\dfrac{x}{7}=\dfrac{y}{3}=\dfrac{x-y}{7-3}=\dfrac{16}{4}=4\)

\(\Rightarrow\left\{{}\begin{matrix}x=28\\y=12\end{matrix}\right.\)