\(a,\Leftrightarrow4^x\left(1+4^3\right)=4160\\ \Leftrightarrow4^x=4160:65=64=4^3\\ \Leftrightarrow x=3\\ b,\Leftrightarrow2^{x-2}\left(2+5\right)=\dfrac{7}{32}\\ \Leftrightarrow2^{x-2}=\dfrac{7}{32}:7=\dfrac{1}{32}=2^{-5}\\ \Leftrightarrow x-2=-5\Leftrightarrow x=-3\)
a: \(\Leftrightarrow4^x\cdot65=4160\)
hay x=3
b: \(\Leftrightarrow2^{x-1}\cdot\dfrac{7}{2}=\dfrac{7}{32}\)
\(\Leftrightarrow x=-3\)