\(\left(x+\dfrac{1}{2}\right)^2=x^2+x+\dfrac{1}{4}\\ \left(5+3x\right)^2=25+30x+9x^2\\ \left(4-a\right)^2=16-8a+a^2\\ \left(3x-2\right)^2=9x^2-12x+4\\ \left(x+2\right)\left(x-2\right)=x^2-4\\ \left(x+2\right)\left(x^2-2x+4\right)=x^3+8\\ \left(x-3\right)\left(x^2+3x+9\right)=x^3-27\)
\(\left(x+\dfrac{1}{2}\right)^2=x^2+x+\dfrac{1}{4}\)
\(\left(4-a\right)^2=16-8a+a^2\)
\(\left(x+2\right)\left(x-2\right)=x^2-4\)
\(\left(5+3x\right)^3=125+225x+135x^2+27x^3\)
\(\left(3x-2\right)^3=27x^3-54x^2+36x-8\)
\(\left(x+2\right)\left(x^2-2x+4\right)=x^3+8\)
\(\left(x-3\right)\left(x^2+3x+9\right)=x^3-27\)
