Question

Answer 1

\(\dfrac{\left(3x-2\right)\left(x+1\right)-\left(2x+5\right)\left(x^2-1\right)}{x+1}\)

\(=3x-2-\left(2x+5\right)\left(x-1\right)\)

Answer 2

\(=\left[\left(3x-2\right)\left(x+1\right)-\left(2x+5\right)\left(x-1\right)\left(x+1\right)\right]:\left(x+1\right)\)

\(=\left\{\left(x+1\right)\left[\left(3x-2\right)-\left(2x+5\right)\left(x-1\right)\right]\right\}:\left(x+1\right)\)

\(=3x-2-2x^2-3x+5=-2x^2-3\)