Question

Answer 1

\(=\dfrac{2\sqrt{x}-1-\sqrt{x}+2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}:\dfrac{2\sqrt{x}-1-\sqrt{x}+2}{\sqrt{x}-2}\)

\(=\dfrac{\sqrt{x}+1}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}.\dfrac{\sqrt{x}-2}{\sqrt{x}+1}=\dfrac{1}{\sqrt{x}+2}\)

Answer 2

 

=√x+1/(√x−2)(√x+2).√x−2√x+1=1√x+2