a) \(A=4x-x^2=-\left(x^2-4x+4\right)+4=-\left(x-2\right)^2+4\le4\)
Dấu "=" xảy ra \(\Leftrightarrow x=2\)
vậy \(A_{min}=4\Leftrightarrow x=2\)
b) \(B=4x-x^2+3=-\left(x^2-4x+4\right)+7=-\left(x-2\right)^2+7\le7\)
Dấu "=" xảy ra \(\Leftrightarrow x=2\)
vậy \(B_{min}=7\Leftrightarrow x=2\)


