ĐKXĐ: \(x\le4\)
\(P=x+\sqrt{4-x}=-\left(4-x-\sqrt{4-x}+\dfrac{1}{4}\right)+\dfrac{17}{4}\)
\(=-\left(\sqrt{4-x}-\dfrac{1}{2}\right)^2+\dfrac{17}{4}\le\dfrac{17}{4}\)
\(maxP=\dfrac{17}{4}\Leftrightarrow\sqrt{4-x}=\dfrac{1}{2}\)
\(\Leftrightarrow4-x=\dfrac{1}{4}\Leftrightarrow x=\dfrac{15}{4}\left(tm\right)\)

