Question

Answer 1

\(1,ĐK:x\ge0\\ PT\Leftrightarrow\sqrt{x}+2\sqrt{x}-\dfrac{1}{3}\cdot3\sqrt{x}=6\\ \Leftrightarrow2\sqrt{x}=6\Leftrightarrow\sqrt{x}=3\\ \Leftrightarrow x=9\left(tm\right)\\ 2,ĐK:x\ge-1\\ PT\Leftrightarrow x+3=x^2+2x+1\\ \Leftrightarrow x^2+x-2=0\\ \Leftrightarrow\left(x+2\right)\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\left(ktm\right)\\x=1\left(tm\right)\end{matrix}\right.\Leftrightarrow x=1\)

Answer 2