\(\sqrt{\left(2x+3\right)^2}=6\)
\(\left(\sqrt{\left(2x+3\right)^2}\right)^2=6^2\)
\(\left(2x+3\right)^2=36\)
⇒\(\left[{}\begin{matrix}2x+3=6\\2x+3=-6\end{matrix}\right.\)
⇒\(\left[{}\begin{matrix}2x=3\\2x=-9\end{matrix}\right.\)
⇒\(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{9}{2}\end{matrix}\right.\)

