a) \(=\dfrac{2\sqrt{3}\left(\sqrt{3}+1\right)+12\left(\sqrt{3}-1\right)}{\sqrt{3}\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)}-\dfrac{\sqrt{3}+2}{3-4}\)
\(=\dfrac{2\sqrt{3}\left(\sqrt{3}+1+6-2\sqrt{3}\right)}{\sqrt{3}\left(3-1\right)}+\sqrt{3}+2\)
\(=7-\sqrt{3}+\sqrt{3}+2=9\)
b) \(=\dfrac{\left(\sqrt{2}+1\right)^2-\left(\sqrt{2}-1\right)^2}{\left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right)}-\dfrac{\sqrt{2}\left(4\sqrt{2}-1\right)}{\sqrt{2}}\)
\(=4\sqrt{2}-4\sqrt{2}+1=1\)
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