a: Ta có: \(\left(x-5\right)^2=\left(2x+3\right)^2\)
\(\Leftrightarrow\left(2x+3+x-5\right)\left(2x+3-x+5\right)=0\)
\(\Leftrightarrow\left(x+8\right)\left(3x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-8\\x=\dfrac{2}{3}\end{matrix}\right.\)