Question

Answer 1

\(x=180^0-\dfrac{1}{2}\widehat{B}-\dfrac{1}{2}\widehat{C}=180^0-\dfrac{1}{2}\left(\widehat{B}+\widehat{C}\right)\\ =180^0-\dfrac{1}{2}\left(180^0-\widehat{A}\right)=180^0-\dfrac{1}{2}\cdot115^0=122,5^0\\ y=180^0-\left(\widehat{B}+\widehat{C}\right)=180^0-2\left(\widehat{IBC}+\widehat{ICB}\right)\\ =180^0-2\left(180^0-\widehat{BIC}\right)=180^0-2\cdot60^0=60^0\)

Answer 2

\(x=180^0-\dfrac{180^0-65^0}{2}=122.5^0\)

\(y=180^0-2\cdot60^0=60^0\)