\(1,\\ D=6\sqrt{2}-42\sqrt{2}-7\sqrt{2}=-43\sqrt{2}\\ E=\sqrt{\left(\sqrt{5}-\sqrt{3}\right)^2}+\sqrt{\left(\sqrt{3}+1\right)^2}-\sqrt{5}\\ E=\sqrt{5}-\sqrt{3}+\sqrt{3}+1-\sqrt{5}=1\\ F=\dfrac{2\sqrt{5}+2\sqrt{2}+2\sqrt{5}-2\sqrt{2}}{\left(\sqrt{5}-\sqrt{2}\right)\left(\sqrt{5}+\sqrt{2}\right)}=\dfrac{4\sqrt{5}}{3}\)
\(2,\\ a,ĐK:x\le\dfrac{3}{2}\\ PT\Leftrightarrow\sqrt{3-2x}=4\Leftrightarrow3-2x=16\Leftrightarrow x=-\dfrac{13}{2}\left(tm\right)\\ b,ĐK: x\ge3\\ PT\Leftrightarrow\sqrt{x-3}+2\sqrt{x-3}-2\cdot3\sqrt{x-3}=-3\\ \Leftrightarrow-3\sqrt{x-3}=-3\Leftrightarrow\sqrt{x-3}=1\\ \Leftrightarrow x-3=1\Leftrightarrow x=4\left(tm\right)\)
