Bài 2:
1: \(\left(x-\frac12\right)^2=\frac94\)
=>\(\left[\begin{array}{l}x-\frac12=\frac32\\ x-\frac12=-\frac32\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac32+\frac12=\frac42=2\\ x=-\frac32+\frac12=-\frac22=-1\end{array}\right.\)
2: \(\left(2x+\frac32\right)^3=-\frac{8}{125}\)
=>\(2x+\frac32=-\frac25\)
=>\(2x=-\frac25-\frac32=\frac{-4-15}{10}=-\frac{19}{10}\)
=>\(x=-\frac{19}{20}\)
3: \(\frac34-\left|x-\frac13\right|=-\frac56\)
=>\(\left|x-\frac13\right|=\frac34+\frac56=\frac{9}{12}+\frac{10}{12}=\frac{19}{12}\)
=>\(\left[\begin{array}{l}x-\frac13=\frac{19}{12}\\ x-\frac13=-\frac{19}{12}\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac{19}{12}+\frac13=\frac{23}{12}\\ x=-\frac{19}{12}+\frac13=-\frac{15}{12}=-\frac54\end{array}\right.\)
4: \(-\frac12+\frac35x=-\frac12\)
=>\(\frac35x=-\frac12+\frac12=0\)
=>x=0
5: \(\frac{32}{x+1}=\frac{-8}{4}\)
=>\(x+1=32\cdot\frac{4}{-8}=-16\)
=>x=-16-1
=>x=-17
6: \(\frac{1}{x+1}=\frac{x+1}{81}\)
=>\(\left(x+1\right)^2=1\cdot81=81\)
=>\(\left[\begin{array}{l}x+1=9\\ x+1=-9\end{array}\right.\Rightarrow\left[\begin{array}{l}x=8\\ x=-10\end{array}\right.\)
Bài 1:
1: \(-\frac{5}{12}+\frac{4}{37}-\frac{7}{12}-\frac{41}{37}+\frac12\)
\(=\left(-\frac{5}{12}-\frac{7}{12}\right)+\left(\frac{4}{37}-\frac{41}{37}\right)+\frac12\)
\(=-1-1+\frac12=-\frac32\)
2: \(26\frac17:\left(-\frac34\right)-44\frac17:\left(-\frac34\right)\)
\(=\left(26+\frac17-44-\frac17\right):\left(-\frac34\right)\)
\(=-18\cdot\left(-\frac43\right)=24\)
