Question

Answer 1

a: \(\left(-\frac{28}{19}\right)\cdot\left(-\frac{38}{14}\right)=\frac{28}{14}\cdot\frac{38}{19}=2\cdot2=4\)

b: \(-\left(-\frac{21}{16}\right)\cdot\left(-\frac{24}{7}\right)=-\frac{21}{16}\cdot\frac{24}{7}=-\frac{21}{7}\cdot\frac{24}{16}=-3\cdot\frac32=-\frac92\)

c: \(\frac{-12}{7}\cdot1,25=\frac{-12\cdot1,25}{7}=-\frac{15}{7}\)

d: \(-\frac45\cdot3\frac{2}{16}=-\frac45\cdot\frac{35}{16}=\frac{-4}{16}\cdot\frac{35}{5}=\frac{-1}{4}\cdot7=-\frac74\)

e: \(12\cdot\left(-\frac23\right)^2=12\cdot\frac49=\frac{48}{9}=\frac{16}{3}\)

f: \(\left(-2\right)\cdot\frac{-38}{21}\cdot\frac{-7}{4}\cdot\left(-\frac38\right)=2\cdot\frac74\cdot\frac38\cdot\frac{38}{21}=\frac{2}{4\cdot8}\cdot38=\frac{2\cdot2\cdot19}{4\cdot8}=\frac{19}{8}\)

g: \(2\frac23\cdot\frac25\cdot\frac38\cdot10\cdot\frac{19}{92}\)

\(=\frac53\cdot\frac25\cdot\frac38\cdot10\cdot\frac{19}{92}=\frac{2\cdot10}{8}\cdot\frac{19}{92}=\frac{20}{8}\cdot\frac{19}{92}=\frac{19}{92}\cdot\frac52=\frac{95}{184}\)

h: \(P=-\frac{8}{13}\cdot\frac{16}{9}\cdot\frac{-13}{8}\cdot\left(-18\right)=-18\cdot\frac{16}{9}=-2\cdot16=-32\)