5x=2y
=>\(\frac{x}{2}=\frac{y}{5}\)
Đặt \(\frac{x}{2}=\frac{y}{5}=k\)
=>x=2k; y=5k
\(x^3+y^3=133\)
=>\(\left(2k\right)^3+\left(5k\right)^3=133\)
=>\(8k^3+125k^3=133\)
=>\(133k^3=133\)
=>\(k^3=1\)
=>k=1
=>\(\begin{cases}x=2\cdot1=2\\ y=5\cdot1=5\end{cases}\)
