\(a,=\dfrac{6-4\sqrt{2}-6-4\sqrt{2}}{\left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right)}=-8\sqrt{2}\\ b,=\left[\dfrac{\left(\sqrt{2}+\sqrt{3}\right)\left(2+\sqrt{6}+3\right)}{\sqrt{2}+\sqrt{3}}-\sqrt{6}\right]:\left(\sqrt{2}-\sqrt{3}\right)-\dfrac{2\sqrt{6}\left(\sqrt{3}-\sqrt{2}\right)}{3-2}\\ =\dfrac{5+\sqrt{6}-\sqrt{6}}{\sqrt{2}-\sqrt{3}}-2\sqrt{6}\left(\sqrt{3}-\sqrt{2}\right)\\ =\dfrac{5\left(\sqrt{3}+\sqrt{2}\right)}{2-3}-6\sqrt{2}+4\sqrt{3}\\ =-5\sqrt{3}-5\sqrt{2}-6\sqrt{2}+4\sqrt{3}=-11\sqrt{2}-\sqrt{3}\)
a) \(=\dfrac{6-4\sqrt{2}-6-4\sqrt{2}}{9-8}=-8\sqrt{2}\)
b) \(=\left[\dfrac{\left(\sqrt{2}+\sqrt{3}\right)\left(2-\sqrt{6}+3\right)}{\sqrt{2}+\sqrt{3}}-\sqrt{6}\right].\dfrac{1}{\sqrt{2}-\sqrt{3}}-\dfrac{2\sqrt{6}\left(\sqrt{3}-\sqrt{2}\right)}{3-2}\)
\(=\dfrac{\left(5-2\sqrt{6}\right)\left(\sqrt{3}+\sqrt{2}\right)}{3-2}-6\sqrt{2}+4\sqrt{3}=5\sqrt{3}+5\sqrt{2}-6\sqrt{2}-4\sqrt{3}-6\sqrt{2}+4\sqrt{3}=5\sqrt{3}-7\sqrt{2}\)
