Bài 3:
b: \(\dfrac{1}{3}B=\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{102}}\)
\(\Leftrightarrow B\cdot\dfrac{-2}{3}=\dfrac{1}{3^{102}}-\dfrac{1}{3}\)
\(\Leftrightarrow B=\left(\dfrac{1-3^{101}}{3^{102}}\cdot\dfrac{-2}{3}\right)=\dfrac{-2+2\cdot3^{101}}{3^{103}}\)
