Đặt \(A=4^{2017}+4^{2016}+\cdots+4+1\)
=>\(4A=4^{2018}+4^{2017}+\cdots+4^2+4\)
=>4A-A=\(4^{2018}+4^{2017}+\cdots+4^2+4-4^{2017}-4^{2016}-\cdots-4-1\)
=>3A=\(4^{2018}-1\)
\(M=75\left(4^{2017}+4^{2016}+\cdots+4+1\right)+25\)
\(=25\cdot3A+25\)
=25(3A+1)
\(=25\cdot\left(4^{2018}-1+1\right)=25\cdot4^{2018}=100\cdot4^{2017}\)
=>M⋮100
