Question

Answer 1

\(\left(x^2+2x+4\right)\left(2-x\right)+x\left(x-3\right)\left(x+4\right)-x^2+24=0\)

\(\Leftrightarrow-\left(x-2\right)\left(x^2+2x+4\right)+x\left(x^2+x-12\right)-x^2+24=0\)

\(\Leftrightarrow-x^3+8+x^3+x^2-12x-x^2+24=0\)

\(\Leftrightarrow-12x=-32\)

hay \(x=\dfrac{8}{3}\)