Bài 6:
a: \(\left\lbrack\left(8x-12\right):4\right\rbrack\cdot3^3=3^6\)
=>\(2x-3=3^6:3^3=3^3=27\)
=>2x=27+3=30
=>x=15
b: \(3^{2x-4}-x^0=8\)
=>\(3^{2x-4}=1+8=9=3^2\)
=>2x-4=2
=>2x=6
=>x=3
c: \(65-4^{x+2}=2021^0\)
=>\(65-4^{x+2}=1\)
=>\(4^{x+2}=65-1=64=4^3\)
=>x+2=3
=>x=1
d: \(5^{2x-3}-2\cdot5^3=5^3\cdot3\)
=>\(5^{2x-3}=5^3\cdot2+5^3\cdot2=5^4\)
=>2x-3=4
=>2x=7
=>x=7/2
e: \(740:\left(x+10\right)=10^2-2\cdot13\)
=>740:(x+10)=100-26=74
=>x+10=10
=>x=0
f: \(2\cdot3^{x}=10\cdot3^{12}+8\cdot27^4\)
=>\(2\cdot3^{x}=10\cdot3^{12}+8\cdot3^{12}=18\cdot3^{12}=2\cdot3^{14}\)
=>\(3^{x}=3^{14}\)
=>x=14
g: \(15:\left(x+2\right)=\left(3^3+3\right):10\)
=>15:(x+2)=(27+3):10=30:10=3
=>x+2=5
=>x=3
h: \(4\cdot\left(3x-1\right)^3-5^2=475\)
=>\(4\cdot\left(3x-1\right)^3=25+475=500\)
=>\(\left(3x-1\right)^3=125\)
=>3x-1=5
=>3x=6
=>x=2
i: \(\left(4x-1\right)^3=27\cdot125\)
=>\(\left(4x-1\right)^3=3^3\cdot5^3=15^3\)
=>4x-1=15
=>4x=16
=>x=4
