Bài 7:
\(\left|\overrightarrow{AB}+\overrightarrow{BC}\right|=\left|\overrightarrow{AC}\right|=3a\)
\(\left|\overrightarrow{CA}-\overrightarrow{CB}\right|=\left|\overrightarrow{BA}\right|=a\)
\(\left|\overrightarrow{AB}-\overrightarrow{AC}\right|=\left|\overrightarrow{CB}\right|=a\sqrt{10}\)