\(ĐK:x\ge-3\\ PT\Leftrightarrow2\sqrt{x+3}-3\cdot\dfrac{1}{3}\sqrt{x+3}+\dfrac{3}{5}\cdot5\sqrt{x+3}=2\\ \Leftrightarrow4\sqrt{x+3}=2\\ \Leftrightarrow\sqrt{x+3}=\dfrac{1}{2}\Leftrightarrow x+3=\dfrac{1}{4}\Leftrightarrow x=-\dfrac{11}{4}\left(tm\right)\)

