a) \(2\sqrt{12}+\dfrac{1}{5}\sqrt{75}-\sqrt{108}=4\sqrt{3}+\sqrt{3}-6\sqrt{3}=-\sqrt{3}\)
b) \(\sqrt{4\dfrac{1}{2}}-\dfrac{1}{3}\sqrt{162}-\dfrac{1}{\sqrt{2}}+\sqrt{3-2\sqrt{2}}=\dfrac{3\sqrt{2}}{2}-3\sqrt{2}-\dfrac{\sqrt{2}}{2}+\sqrt{\left(\sqrt{2}-1\right)^2}=\left(\dfrac{3\sqrt{2}}{2}-\dfrac{\sqrt{2}}{2}\right)-3\sqrt{2}+\sqrt{2}-1=\sqrt{2}-2\sqrt{2}-1=-1-\sqrt{2}\)

