Question

Answer 1

\(a,ĐK:x\ge3\\ PT\Leftrightarrow\sqrt{x-3}=\sqrt{5}-1\\ \Leftrightarrow x-3=6-2\sqrt{5}\\ \Leftrightarrow x=9-2\sqrt{5}\left(tm\right)\\ b,ĐK:x\in R\\ PT\Leftrightarrow\left|4x-3\right|=5\Leftrightarrow\left[{}\begin{matrix}4x-3=5\left(x\ge\dfrac{3}{4}\right)\\3-4x=5\left(x< \dfrac{3}{4}\right)\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2\left(tm\right)\\x=\dfrac{1}{2}\left(tm\right)\end{matrix}\right.\\ c,ĐK:x\ge\dfrac{1}{2}\\ PT\Leftrightarrow6\cdot\dfrac{1}{3}\sqrt{2x-1}+2\sqrt{2x-1}-3\sqrt{2x-1}=3\\ \Leftrightarrow\sqrt{2x-1}=3\Leftrightarrow2x-1=9\Leftrightarrow x=5\left(tm\right)\)