Question

Answer 1

Bài 2:

a: Ta có: \(\hat{xOt}+\hat{tOy}=\hat{xOy}\) (tia Ot nằm giữa hai tia Ox và Oy)

=>\(\hat{xOt}=\hat{xOy}-90^0\left(1\right)\)

Ta có: \(\hat{yOz}+\hat{xOz}=\hat{xOy}\) (tia Oz nằm giữa hai tia Ox và Oy)

=>\(\hat{yOz}=\hat{xOy}-90^0\left(2\right)\)

Từ (1),(2) suy ra \(\hat{xOt}=\hat{yOz}\)

b: \(\hat{xOy}+\hat{zOt}\)

\(=\hat{xOt}+\hat{tOz}+\hat{zOy}+\hat{zOt}\)

\(=2\left(\hat{xOt}+\hat{tOz}\right)=2\cdot\hat{xOz}=2\cdot90^0=180^0\)