Question

Answer 1

c: Ta có: \(4^x+4^{x+3}=4160\)

\(\Leftrightarrow4^x=64\)

hay x=3

Answer 2

b: Ta có: \(\left(4x-1\right)^2=\left(1-4x\right)^3\)

\(\Leftrightarrow\left(4x-1\right)^3+\left(4x-1\right)^2=0\)

\(\Leftrightarrow4x\left(4x-1\right)^2=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{4}\end{matrix}\right.\)