\(a,\Rightarrow2-x=0\Rightarrow x=2\\ b,\Rightarrow\left[{}\begin{matrix}3x-4=2\left(x\ge\dfrac{4}{3}\right)\\4-3x=2\left(x< \dfrac{4}{3}\right)\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\left(tm\right)\\x=\dfrac{2}{3}\left(tm\right)\end{matrix}\right.\)
\(c,\Rightarrow x\in\varnothing\left(\left|x-0,5\right|\ge0>-2,5\right)\\ d,\Rightarrow5\left|x-0,5\right|=-\dfrac{2}{5}+2=\dfrac{8}{5}\\ \Rightarrow\left|x-0,5\right|=\dfrac{8}{25}=0,32\\ \Rightarrow\left[{}\begin{matrix}x-0,5=0,32\left(x\ge0,5\right)\\0,5-x=0,32\left(x< 0,5\right)\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0,82\left(tm\right)\\x=0,18\left(tm\right)\end{matrix}\right.\)
a: Ta có: |2-x|=0
nên 2-x=0
hay x=2
b: Ta có: |3x-4|=2
\(\Leftrightarrow\left[{}\begin{matrix}3x-4=2\\3x-4=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{2}{3}\end{matrix}\right.\)
\(a,\left|2-x\right|=0\)
\(\Rightarrow2-x=0\)
\(\Rightarrow x=2\)
\(b,\left|3x-4\right|=2\)
\(\Rightarrow\left[{}\begin{matrix}3x-4=2\\3x-4=-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}3x=6\\3x=2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{2}{3}\end{matrix}\right.\)
\(c,\left|x-0,5\right|=-2,5\)
Vì: \(\left|x-0,5\right|\ge0\forall x\)
Mà: \(\left|x-0,5\right|=-2,5\) (vô lí)
\(\Rightarrow x\in\varnothing\)
\(d,5\left|x-0,5\right|-2=-\left|-\dfrac{2}{5}\right|\)
\(\Rightarrow5\left|x-0,5\right|-2=-0,4\)
\(\Rightarrow5\left|x-0,5\right|=1,6\)
\(\Rightarrow\left|x-0,5\right|=0,32\)
\(\Rightarrow\left[{}\begin{matrix}x-0,5=0,32\\x-0,5=-0,32\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0.82\\x=0,18\end{matrix}\right.\)
