Question

Answer 1

\(a,I=\dfrac{\left(x-1\right)\left(x+1\right)}{\left(x-1\right)^2}=\dfrac{x+1}{x-1}=\dfrac{-1+1}{-1-1}=0\\ b,M=\dfrac{\left(-2\right)^4+8}{\left(-2\right)^2-2\left(-2\right)+4}=\dfrac{16+8}{4+2+4}=\dfrac{24}{10}=\dfrac{12}{5}\\ c,K=27+x^3-27=x^3=\left(-3\right)^3=-27\)

Answer 2

\(I=\dfrac{x^2-1}{x^2-2x+1}=\dfrac{\left(x-1\right)\left(x+1\right)}{\left(x-1\right)^2}=\dfrac{x+1}{x-1}=\dfrac{-1+1}{-1-1}=0\)

\(M=\dfrac{x^3+8}{x^2-2x+4}=x+2=-2+2=0\)

\(K=27+\left(x-3\right)\left(x^2+3x+9\right)=x^3=-27\)