Bài 2:
a: \(x+\dfrac{4}{15}=\dfrac{1}{12}\)
\(\Leftrightarrow x=\dfrac{1}{12}-\dfrac{4}{15}=\dfrac{15-48}{180}=\dfrac{-33}{180}=\dfrac{-11}{60}\)
b: \(x-\dfrac{5}{8}=1\dfrac{2}{3}\)
\(\Leftrightarrow x=\dfrac{5}{3}+\dfrac{5}{8}=\dfrac{40+15}{24}=\dfrac{55}{24}\)

4 và 5