\(1,=5+\sqrt{11}+5-\sqrt{11}=10\\ 2,=\left(\sqrt{5}+1\right)+\left(\sqrt{5}-1\right)=2\sqrt{5}\\ 3,=5-\sqrt{13}-\left(4-\sqrt{13}\right)=1\\ 4,=\left(\sqrt{7}+1\right)-\left(\sqrt{7}-1\right)=2\\ 5,=\left(3+\sqrt{6}\right)+\left(5-\sqrt{6}\right)=8\\ 6,=\left(3+\sqrt{2}\right)+\left(\sqrt{2}-1\right)=2+2\sqrt{2}\)
1=\(\sqrt{11}+5+5-\sqrt{11}\)=10
2.=\(\sqrt{\left(\sqrt{5}+1\right)^2}+\sqrt{\left(\sqrt{5}-1\right)^2}\)=\(\sqrt{5}+1+\sqrt{5}-1\)=\(2\sqrt{5}\)
3.\(5-\sqrt{13}-4+\sqrt{13}\)=1
4.\(\sqrt{\left(\sqrt{7}+1\right)^2}-\sqrt{\left(\sqrt{7}-1\right)^2}\)=\(\sqrt{7}+1-\sqrt{7}+1=2\)
5.\(\sqrt{6}+3+5-\sqrt{6}\)=8
6.\(\sqrt{\left(3+\sqrt{2}\right)^2}+\sqrt{\left(\sqrt{2}-1\right)^2}=3+\sqrt{2}+\sqrt{2}-1\)
=\(2+2\sqrt{2}\)
