a) ĐKXĐ: \(x\ne1\)
b) \(B=\left(\dfrac{x+1}{2x-2}+\dfrac{3}{x^2-1}-\dfrac{x+3}{2x+2}\right).\dfrac{4x^2-4}{5}\)
\(=\dfrac{\left(x+1\right)^2+6-\left(x+3\right)\left(x-1\right)}{2\left(x^2-1\right)}.\dfrac{4\left(x^2-1\right)}{5}\)
\(=\left(x^2+2x+1+6-x^2-2x+3\right).\dfrac{2}{5}\)
\(=10.\dfrac{2}{5}=4\left(đpcm\right)\)

